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Good day I have the following snippet:

#! /usr/bin/python
#! /usr/bin/python3

from sys import version_info
import logging

py3 = version_info[0] > 2 

if py3:
    name = input('What is your name?: ')
    verify_user(name)
else:
    name = raw_input('What is your name?: ')
    verify_user(name)


def verify_user(name):
    if name is not 'My Admin':
        logging.warning('What the hell are you doing in here ???')
    else:
        logging.info('Welcome Dear Admin')

When I run it through the shell doing: ./log.py, I'm receiving the following error: 

verify_user is not define.

Not sure what is going on. I have defined the verify_user(). Any help will be really appreciated.

the phenom
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2 Answers2

4

You're calling verify_user before you define it. Move the verify_user function to the top of your file.

#! /usr/bin/python 
#! /usr/bin/python3

from sys import version_info
import logging

def verify_user(name):
    if name is not 'My Admin':
        logging.warning('What the hell are you doing in here ???')
    else:
        logging.info('Welcome Dear Admin')

py3 = version_info[0] > 2 

if py3:
    name = input('What is your name?: ')
    verify_user(name)
else:
    name = raw_input('What is your name?: ')
    verify_user(name)
Anthony E
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  • when I run this snippet no matter what my keyboard input is, it's just showing the logging.warning(), while what I want is when the name input equals My Admin, to display the else part. – the phenom May 16 '16 at 10:48
1

Python is a dynamic language, hence you need to 1st define the function and then use it.

Solution: Put the whole function definition before using it.

#! /usr/bin/python
#! /usr/bin/python3

from sys import version_info
import logging

def verify_user(name):
    if name is not 'My Admin':
        logging.warning('What the hell are you doing in here ???')
    else:
        logging.info('Welcome Dear Admin')

py3 = version_info[0] > 2 

if py3:
    name = input('What is your name?: ')
    verify_user(name)
else:
    name = raw_input('What is your name?: ')
    verify_user(name)
riteshtch
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  • 4
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  • @ritesht93, when I run this snippet no matter what my keyboard input is, it's just showing the logging.warning(), while what I want is when the name input equals My Admin, to display the else part. – the phenom May 16 '16 at 10:49
  • @thePhenom use `!=` instead of `is not` – riteshtch May 16 '16 at 11:00