Yield return a bunch of elements

Question

I have a method that returns a list of MyClass. Within that method I split a list of MyClass into smaller chunks of let´s say 500 elements. Now I wonder if this is possible together with a yield-statement. Currently I have this code. However I´m curious if there is a way to yield return the whole bunch without this messy second inner loop.

IEnumerable<MyClass> DoSomething() 
{
    List<MyClass> myList = ...
    foreach(var chunk in myList.Chunk(500))  // split the list in smaller lists
    {
        foreach(MyClass m in chunk) yield return m;
    }
}

Of course this works, but I wonder if I can also use the yield to return the whole bunch deferredly.

@TrevorPilley Sure, see on http://stackoverflow.com/questions/419019/split-list-into-sublists-with-linq/20953521#20953521 — MakePeaceGreatAgain, May 27 '16 at 13:21
The duplicate is what I already feared: it is not possible to do so. Either return a list of lists as suggested by Sean or iterate the elements of every bunch and yield it back. — MakePeaceGreatAgain, May 27 '16 at 13:24

score 0 · Answer 1 · answered May 27 '16 at 13:22

Assuming that Chunk returns some sort of List<> you could do:

IEnumerable<IList<MyClass>> DoSomething() 
{
    List<MyClass> myList = ...
    foreach(var chunk in myList.Chunk(500))  // split the list in smaller lists
    {
        yield return chunk;
    }
}

Yield return a bunch of elements

1 Answers1