I cannot understand how the "if" and "or" are working here

Asked Jun 02 '16 at 13:07

Active Jun 02 '16 at 13:47

Viewed 39 times

if player[2] != (0 or 4 or 7 or 10 or 30):
    print("hi")
else:
    print("bye")

In my program, player[2] is clearly 7. However, when I run this, it returns "hi" instead of "bye". Why? And how would I go about testing that player[2] is not any of these numbers without writing a separate if statement for each?

edited Jun 02 '16 at 13:47

jonrsharpe

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asked Jun 02 '16 at 13:07

ohjuny

1

The parenthesis is evaluated first, and that result is compared to `player[2]` - it's not comparing with each of the element, it just doesn't work like that. – henrikstroem Jun 02 '16 at 13:10
1

Hint: `(0 or 4 or 7 or 10 or 30) is 4` – jonrsharpe Jun 02 '16 at 13:11
So how would I go about fixing it? I know that I could write a separate if statement for each but that seems quite inefficient – ohjuny Jun 02 '16 at 13:17
1

@ohjuny: `if player[2] not in (0, 4, 7, 10, 30):` – ShadowRanger Jun 02 '16 at 13:26
It is absolutely a duplicate, just put things the other way around. – jonrsharpe Jun 02 '16 at 13:48

I cannot understand how the "if" and "or" are working here

0 Answers0