Batch file if statment wont excute set command

Question

@echo off
setlocal enabledelayedexpansion
set chk=tru
set final=c:\users\user1\desktop
set var=c:\users\user1\desktop
    for %%s in (%final%) do (
        echo %%s
        echo %var%
        if %var%==%%s set chk=false
        echo %chk%
    )

the two strings are the same but the if statment wont excute the set command and change the chk variable. can someone please help? im new to batch scripting and i dont understand why this dosent work. i think its a technical matter i just dont know about

you need [delayed expansion](http://stackoverflow.com/a/30284028/2152082) — Stephan, Jun 06 '16 at 16:42

score 0 · Answer 1 · answered Jun 06 '16 at 16:33

in for loop use exclamation marks to reference variable. try this:

@echo off
setlocal enabledelayedexpansion
set chk=tru
set final=c:\users\user1\desktop
set var=c:\users\user1\desktop
    for %%s in (%final%) do (
        echo %%s
        echo %var%
        if {%var%}=={%%s} set chk=false
        echo !chk!
    )

and read about EnableDelayedExpansion

score 0 · Answer 2 · answered Jun 06 '16 at 16:45

Since you are changing the value of chk in the loop itself the changes made gets reflected back only in the next iteration. Thus you need to use ! instead of % to see the change immediately.

@echo off
setlocal enabledelayedexpansion
set chk=tru
set final=c:\users\user1\desktop
set var=c:\users\user1\desktop
    for %%s in (%final%) do (
        echo %%s
        echo %var%
        if %var%==%%s set chk=false
        echo !chk!
    )

Batch file if statment wont excute set command

2 Answers2