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In bash programming If VAR="/home/somestuff/work/OutExample/Air",

How to get "workOutExampleAir" ?

Thanks

Tuni
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1 Answers1

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 cut -f4- -d/ --output-delimiter ""  <<< "$var"

cut utility takes field from 4 with delimiter /

in bash

name=$(cut -f4- -d/ --output-delimiter ""  <<< "$var")
echo "$name"
Chet
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    Remember your quotes around parameter expansions: `<<< "$VAR"` and `echo "$NAME"`. Also you shouldn't use uppercase variable names as they are reserved to environment variables. – Andreas Louv Jun 07 '16 at 18:00