How this works?
void function() {}()
I saw an explanation that void transforms the iife from declaration to expression, and every expression must be evaluated, is this right?
Thanks.
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What you've shown is not an IIFE - nothing is invoked here. – Bergi Jun 10 '16 at 02:18
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I've updated the question @Bergi. – Jun 10 '16 at 02:19
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Have a look [here](https://stackoverflow.com/questions/28828348/difference-between-using-void-vs-wrapping-in-parens-for-iife-void-function-vs) – Bergi Jun 10 '16 at 02:21
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When using an immediately-invoked function expression, void can be used to force the function keyword to be treated as an expression instead of a declaration. Check this link at MDN
Hector Barbossa
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Is `var x = void function() { return 1; } ()` valid and if yes, does it assign 1 or undefined? – le_m Jun 10 '16 at 02:59
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When using an immediately-invoked function expression, void can be used to force the function keyword to be treated as an expression instead of a declaration.
Readup: void operator - Javascript | MDN
Rahul Desai
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