How can I add " around each line bash

Question

I have a file with one word on each line, I want to add a " before the word, and a ", after the word with Bash.

Example:

Hello
Sleep
Try

And I want:

"Hello",
"Sleep",
"try",

Hope anyone can help me

Do you want to add the quotes and comma around each word, or each line? (maybe that's the same thing in your case?) — Aaron, Jun 17 '16 at 15:45
Why does the title say you want to add ".", but the question says you want to add quotes and comma? — Barmar, Jun 17 '16 at 15:47

score 10 · Accepted Answer · answered Jun 17 '16 at 15:48

10

sed 's/.*/"&",/' file

In the replacement part of a substitution, & is replaced with whatever matched the original regular expression. .* matches the whole line.

answered Jun 17 '16 at 15:48

Barmar

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score 3 · Answer 2 · answered Jun 17 '16 at 15:51

Assuming you've got one word per line, I'd use the following GNU sed command :

sed -i 's/.*/"\0",/' <your_file>

Where you replace <your_file> by the path to your file.

Explanation :

sed means Stream EDitor ; it specialise in filtering and transforming text streams
-i is it's in-place option : it means it will write the result of its transformation in the file it's working on
s/search/replace/ is sed's search & replace command : it search for a pattern written as regular expression, and replace the matched text by something else
.* is a regex pattern that will match as much as it can. Since sed works line by line, it will match a whole line
\0 is a back-reference to the whole matched string
"\0", is the whole matched string, enclosed in quotes, followed by a comma.
s/.*/"\0",/ is a sed search&replace command that will match a whole line and enclose it in quotes, following it by a comma

bishop · Answer 3 · 2016-06-17T15:53:06.273

2

sed (the Stream EDitor) is one choice for this manipulation:

sed -e 's/^/"/;s/$/",/' file

There are two parts to the regular expression, separated by ;:

s/^/"/ means add a " to the beginning of each line.
s/$/",/ means add a ", to the end of each line.

The magic being the anchors for start of line (^) and end of line ($). The man page has more details. It's worth learning sed.

edited Jun 17 '16 at 15:53

answered Jun 17 '16 at 15:46

bishop

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`g` is redundant here, or am I missing something? – Patrick Trentin Jun 17 '16 at 15:51
1

@PatrickTrentin Yep, force of habit. Fixed. – bishop Jun 17 '16 at 15:52
also, you might want to replace `-e` with `-i` – Patrick Trentin Jun 17 '16 at 16:01
@PatrickTrentin When the OP knows how `sed` operates, then he can choose to take the safety off. – bishop Jun 17 '16 at 16:22
never mind, I had some spurious data. (: – Patrick Trentin Jun 17 '16 at 16:26

score 2 · Answer 4 · edited May 23 '17 at 12:18

Already answered here

Using awk

awk '{ print "\""$0"\","}' inputfile

Using pure bash

while read FOO; do
   echo -e "\"$FOO\","
done < inputfile

where inputfile would be a file containing the lines without quotes.

If your file has empty lines, awk is definitely the way to go:

awk 'NF { print "\""$0"\","}' inputfile

NF tells awk to only execute the print command when the Number of Fields is more than zero (line is not empty).

score 1 · Answer 5 · answered Jun 17 '16 at 16:03

1

Just to be different: perl

perl -lne 'print qq{"$_",}' file

answered Jun 17 '16 at 16:03

glenn jackman

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score 0 · Answer 6 · answered Jun 17 '16 at 15:47

0

This is a simple one liner:

sed -i 's/^/"/;s/$/",/' file_name

answered Jun 17 '16 at 15:47

Patrick Trentin

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score 0 · Answer 7 · edited May 23 '17 at 10:29

0

> echo $word
word
> echo "\""$word"\","
"word",

See How to escape double quotes in bash?

edited May 23 '17 at 10:29

Community

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answered Jun 17 '16 at 15:49

Dan Cornilescu

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You left out the comma. – Barmar Jun 17 '16 at 15:50

How can I add " around each line bash

7 Answers7