my_list = range(1, 11)
print(my_list[::2])
>>> range(1,11,2)
Its not displaying the correct output which should be [1, 3, 5, 7, 9]
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3`range` does not produce a list, no. – Martijn Pieters Jun 21 '16 at 07:02
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https://docs.python.org/3.4/library/stdtypes.html#ranges – SethMMorton Jun 21 '16 at 07:04
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[`range()` doesn't return a list in Py3](https://docs.python.org/3/library/functions.html#func-range). – kylieCatt Jun 21 '16 at 07:04
1 Answers
1
On python3.x, range returns a range object rather than a list. Slicing the range object just returns another range object which is what is displaying in your terminal:
>>> range(1, 11)[::2]
range(1, 11, 2)
>>> type(range(1, 11)[::2])
<class 'range'>
However, iterating over the result should produce the desired elements:
>>> list(range(1, 11)[::2])
[1, 3, 5, 7, 9]
mgilson
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