C++ explicit type is missing('int' assumed)3

Question

enter image description here

Under the display() and evaluate() I get an error code saying that the explicit type is missing('int' assumed). I'm stuck on this part and I'm wondering how I could fix this, would appreciate any assistance.

#pragma warning
#include <iostream>
using namespace std;
class poly {
    int degree;
    int* coeff;

public:
    poly(int);
    poly(poly&);
    poly();
    ~poly();
    display();
    evaluate(int);
    poly operator+(poly&);
    poly operator*(poly&);
};

you should also indent your code correctly, so that it's actually readable. — Sam Varshavchik, Jun 25 '16 at 01:25
Yeah, I haven't done c++ in a while(have been doing java a lot more), I'm trying to brush up on it. — ZuperSoldat, Jun 25 '16 at 01:30

score 2 · Accepted Answer · edited May 23 '17 at 12:16

2

Instead of

display();

write

void display();

And ditto for evaluate.

Tip: you can use free tools like AStyle to format your code with proper indenting.

Tip: The Definitive C++ Book Guide and List provides a nice list of C++ textbooks.

edited May 23 '17 at 12:16

Community

1
1

answered Jun 25 '16 at 01:23

Cheers and hth. - Alf

142,714
15
209
331

Yes, that worked, I feel like an idiot. Thank you so much. – ZuperSoldat Jun 25 '16 at 01:28

C++ explicit type is missing('int' assumed)3

1 Answers1