Java - replace all blank space in String with + sign for URL

Question

So I was looking on StackOverflow for the answer on this question but couldn't find one.

I have an URL whose left and right part are always the same, but the part in a middle changes constantly. If there's only one word it works fine, but if there are multiple the URL brokes.

I need to replace all the whitespace with plus (+) sign.

I'm using this code with no luck:

String content = bioObj.getString("summary");
                    content = content.replaceAll(" ", "%20");
                    bio.setText(content);

Can anyone help?

FULL CODE:

String finalUrlBio = bioUrlLeft+title+bioUrlRight;

        JsonObjectRequest bioRequest = new JsonObjectRequest(Request.Method.GET, finalUrlBio, (JSONObject) null, new Response.Listener<JSONObject>() {
            @Override
            public void onResponse(JSONObject response) {
                try {
                    JSONObject artistObj = response.getJSONObject("artist");
                    JSONObject bioObj = artistObj.getJSONObject("bio");
                    String content = bioObj.getString("summary");
                    content = content.replaceAll("\\s","+");
                    bio.setText(content);


                } catch (JSONException e) {
                    e.printStackTrace();
                }
            }
        }, new Response.ErrorListener() {
            @Override
            public void onErrorResponse(VolleyError error) {

            }
        });

        AppController.getInstance().addToRequestQueue(bioRequest);

ERROR:

07-01 00:00:37.379 2793-2872/com.darioradecic.topmusicandartists E/Volley: [397649] BasicNetwork.performRequest: Unexpected response code 400 for http://ws.audioscrobbler.com/2.0/?method=artist.getinfo&artist=Red Hot Chili Peppers&api_key=99b9ea4e41463638c76b4759d8b1da1d&format=json

string.replace(" ","+") This is the basic to convert all the spaces in a string to + sign — Rakshit Nawani, Jun 30 '16 at 21:52
What didn't work with your attempt? What was the output, or the exception? — Tunaki, Jun 30 '16 at 21:54
Rakshit nope, getting this error: Unexpected response code 400 — DaxHR, Jun 30 '16 at 21:54
You need to add a charset parameter, e.g. `URLEncoder.encode(content, "UTF8");` Can you please provide a full and complete example so that we can reproduce the problem? — Mick Mnemonic, Jun 30 '16 at 21:57
I suppose you are taking "Red Hot Chili Peppers" from a search field, if you are doing so take the text from field and convert it to string and check if contains space the replace " " with "+". Try it and after replacing append the text in your URL — Rakshit Nawani, Jun 30 '16 at 22:21

score 1 · Answer 1 · answered Jun 30 '16 at 22:05

I would just use the replace method. Using your 'content' string:

content.replace(' ', '+');

This will check for a space and replace the space with a plus. If this is a problem when using your entire string due to the beginning and end I would simply substring the middle and then use the replace method. Try https://docs.oracle.com/javase/7/docs/api/java/lang/String.html for all references to a string in java and their predefined references.

Java - replace all blank space in String with + sign for URL

1 Answers1