scanf function skips values in while loop for scanning character value

Question

#include<stdio.h>

int main()
{
    int i,t;
    char c;
    scanf("%d",&t);
    while(t--)
    {
        scanf("%s",&c);
        printf("%c",c);
    }
    return 0;
}

inside the while loop why it skips some of values. but it works okay with integer values

Possible duplicate of [C: Multiple scanf's, when I enter in a value for one scanf it skips the second scanf](http://stackoverflow.com/questions/9562218/c-multiple-scanfs-when-i-enter-in-a-value-for-one-scanf-it-skips-the-second-s) — Thomas Padron-McCarthy, Jul 03 '16 at 17:40
*"inside the while loop why it skips some of values"* What values does it skip? Is there some kind of pattern? Can you describe the problem in more detail? Perhaps by giving sample inputs and outputs? — Cody Gray - on strike, Jul 03 '16 at 17:50
i guess it reads the new line character '\n' when enter is pressed. that is the problem.. — Rishi Sahu, Jul 03 '16 at 17:57

score 2 · Answer 1 · answered Jul 03 '16 at 17:40

2

%s is used to scan strings (not char's), change to %c

answered Jul 03 '16 at 17:40

David Ranieri

39,972
7
52
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actuly it is %c instead of %s. but still. using %c it skips a value. – Rishi Sahu Jul 03 '16 at 17:51
2

@RishiSahu as well as correcting the format spec, put a space in front, as `scanf(" %c",&c);` then it will skip whitespace. `%d` and `%s` do automatically, but `%c` does not, without that little space. – Weather Vane Jul 03 '16 at 18:01

score 1 · Answer 2 · edited May 23 '17 at 11:44

1

this could be a solution. use:

scanf(" %c",&c);

instead of:

scanf("%c",&c);

edited May 23 '17 at 11:44

Community

1
1

answered Jul 03 '16 at 18:13

Matthias Gwiozda

505
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14

scanf function skips values in while loop for scanning character value

2 Answers2