Ignore case for a string in scala

Question

Consider:

object HelloWorld {
  def main(args: Array[String]): Unit = {

    val s:String = "AbcD"

    println(s.contains("ABCD"))
    println(s.contains("AbcD"))

  }
}

Output:

false
true

I need the result to be true in both cases regardless of the case. Is it possible?

http://stackoverflow.com/questions/14018478/string-contains-ignore-case — insan-e, Jul 08 '16 at 14:49

score 25 · Accepted Answer · answered Jul 08 '16 at 13:21

25

If you really need contains use

s.toLowerCase.contains("abcd")

But most likely you are looking for

s.equalsIgnoreCase("abcd")

answered Jul 08 '16 at 13:21

raphaëλ

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5

just pointing out that if the argument to `contains` is dynamic, they would need to call `toLowerCase` on that as well to be case insensitive all around. – jcern Jul 08 '16 at 13:25

score 2 · Answer 2 · answered Jul 08 '16 at 13:47

2

with Regex

println(s.matches("(?i:.*" + "ABCD" + ".*)"))

answered Jul 08 '16 at 13:47

Saqib Ali

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Ignore case for a string in scala

2 Answers2