Else not working in PHP

Question

i have a problem with my code

$save = mysql_real_escape_string($_POST['save']);
$query1 = "SELECT * from users WHERE user_id=".$_SESSION['user'];
$result = mysql_query($query1);

while($row = mysql_fetch_array($result)) {
    // Get money from column
    $money = $row['money'];

    if($money >= $save)

        $query1 = "UPDATE users SET savings = savings + $save, money = money - $save WHERE user_id=".$_SESSION['user'];

        $update1 = mysqli_query($conn,$query1); // call 1st query
        echo 'Money transferred successfully!!!';
    } else  {
        echo 'U NO MONEY IN CHECKING!!!!';
    }
?>

The else statement is not working and I am getting this error:

Parse error: syntax error, unexpected 'else' (T_ELSE) in C:\wamp\www\bank.php on line 44

`if($money >= $save)` should be `if($money >= $save) {` – The Codesee Jul 16 '16 at 17:52 — The Codesee, Jul 16 '16 at 17:52
@TheCodesee its still not working – Mances Karama Jul 16 '16 at 17:54 — Mances Karama, Jul 16 '16 at 17:54

score 0 · Answer 1 · answered Jul 16 '16 at 17:52

0

Please see that you haven't opened a brace { after the if statement.

Change this:

if($money >= $save)

To:

if($money >= $save) {

answered Jul 16 '16 at 17:52

Indrasis Datta

8,692
2
14
32

Still not working bro – Mances Karama Jul 16 '16 at 17:53
You haven't closed the while loop brace. Please close it. – Indrasis Datta Jul 16 '16 at 17:55

score 0 · Answer 2 · answered Jul 16 '16 at 17:52

0

You are missing the opening curly-brace on the if statement:

if($money >= $save) {
    // Here --------^

answered Jul 16 '16 at 17:52

Mureinik

297,002
52
306
350

Else not working in PHP

2 Answers2