Variance calculation returning different answers

Question

In my Java file I constructed a method to work out variance in a list of numbers in a text file.

The function is shown below

public void varience(File commaSeperated) {
    List<String> dataToSplit = new ArrayList<String>();

    try {
        BufferedReader br = new BufferedReader(new FileReader(commaSeperated));
        String currentLine;
        while ((currentLine = br.readLine()) != null) {
            String[] tempArray = currentLine.split(",");
            for(String s : tempArray) {
                dataToSplit.add(s.replaceAll("\t", "").replaceAll("\n", "").trim());
            }
        }

        br.close();
    } catch(Exception e) {
        e.printStackTrace();
    }

    BigDecimal finalD = new BigDecimal("0");
    int count = 0;

    for(String temp : dataToSplit) {
        finalD = finalD.add(new BigDecimal(temp));
        count++;
    }

    System.out.println("Elements: " + count + ", Sum: " + finalD + ", Average: " + (finalD.divide(new BigDecimal(count))));

    BigDecimal average = finalD.divide(new BigDecimal(count));

    count = 0;
    BigDecimal finalVar = new BigDecimal(0);

    for(String temp : dataToSplit) {
        BigDecimal tempBD = ((new BigDecimal(temp)).subtract(average)).pow(2);
        finalVar = finalVar.add(tempBD);
        count++;
        System.out.println("Original Value: " + temp + ", Pass: " + count + ", Adding: " + tempBD + ", CurrentValue: " + finalVar);
    }

    System.out.println(finalVar.divide(new BigDecimal(count))); //This prints the variance
}

The list within the file is as follows

7.1,7.1,7.1,7.1,7.2,7.2,7.2,7.2,7.2,7.2,7.2,7.3,7.3,7.3,7.3,7.3,7.3,7.3,7.3,7.3,7.3,7.3,7.4,7.4,7.4,7.4,7.4,7.4,7.4,7.4,7.4,7.4,7.4,7.4,7.4,7.4,7.4,7.4,7.5,7.5,7.5,7.5,7.5,7.5,7.5,7.5,7.5,7.5,7.5,7.5,7.5,7.5,7.5,7.5,7.5,7.5,7.5,7.5,7.6,7.6,7.6,7.6,7.6,7.6,7.6,7.6,7.6,7.6,7.6,7.6,7.6,7.6,7.6,7.6,7.6,7.6,7.6,7.6,7.7,7.7,7.7,7.7,7.7,7.7,7.7,7.7,7.7,7.7,7.7,7.7,7.7,7.7,7.8,7.8,7.8,7.8,7.8,7.8,7.9,7.9

Using this function the program prints the value of the variance to be 0.034899. However, when I decided to pass the list of numbers through an external source a different value, 0.034898999999923, was returned. This was worked out here.

So the question: Is my code wrong in some way, or truncating the precision of the final value for some reason, or is my code correct and the answer returned by the external source incorrect?