Python not responding in loop

Question

Here is my code:

from random import randint
doorNum = randint(1, 3)
doorInp = input("Please Enter A Door Number Between 1 and 3: ")
x = 1
while (x == 1) :
    if(doorNum == doorInp) :
        print("You opened the wrong door and died.")
        exit()

now, that works fine, if I happen to get the unlucky number.

else :
    print("You entered a room.")
    doorNum = randint(1, 3)

This is the part where it stops responding entirely. I am running it in a bash interactive shell (Terminal, on osx). It just ends up blank.

I am new to programming in Python, I spent most of my time as a web developer.

UPDATE:

Thanks @rawing, I can not yet upvote (newbie), so will put it here.

@Ember can you please explain what is that you intend to achieve, as the logic itself of your program is incorrect — abhinsit, Jul 24 '16 at 07:04
@abhinsit to exit if the user enters a certain number. It is a game. — , Jul 24 '16 at 07:12
@Ember If I had to guess I'd say the downvotes are because this is such an elementary mistake. We get tons of these every single day, so people have a bit of a short fuse sometimes. Don't worry about them too much. People always downvote for mysterious reasons. You should only be worried if your score is below -2. — Aran-Fey, Jul 24 '16 at 07:22

score 0 · Answer 1 · answered Jul 24 '16 at 07:11

0

If you are using python3, then input returns a string and comparing a string to an int is always false, thus your exit() function can never run.

answered Jul 24 '16 at 07:11

xrisk

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score 0 · Answer 2 · answered Jul 24 '16 at 07:28

Your doorInp variable is a string type, which is causing the issue because you are comparing it to an integer in the if statement. You can easily check by adding something like print(type(doorInp)) after your input line. To fix it, just enclose the input statement inside int() like:doorInp = int(input("...."))

score -1 · Accepted Answer · edited May 23 '17 at 12:08

In python3, the input function returns a string. You're comparing this string value to a random int value. This will always evaluate to False. Since you only ask for user input once, before the loop, the user never gets a chance to choose a new number and the loop keeps comparing a random number to a string forever.

I'm not sure what exactly your code is supposed to do, but you probably wanted to do something like this:

from random import randint

while True:
    doorNum = randint(1, 3)
    doorInp = int(input("Please Enter A Door Number Between 1 and 3: "))

    if(doorNum == doorInp) :
        print("You opened the wrong door and died.")
        break

    print("You entered a room.")

See also: Asking the user for input until they give a valid response

Python not responding in loop

3 Answers3