HI How to find last to preview word in xslt i have search to google but not found correct solution can u please help me
MY code is
i have this code as like this
<tag>news/economy/policy/raghuram-rajan-sheds-dogmatism-in-policy-meet-makes-next-rbi-governors-job-easier</tag>
I want to search to last this word "/" and
I want to result is policy
How to do this in xslt .
To do this in pure XSLT 1.0, with no extensions, use:
<xsl:template name="token-before-last">
<xsl:param name="text"/>
<xsl:param name="delimiter" select="'/'"/>
<xsl:variable name="next-text" select="substring-after($text, $delimiter)" />
<xsl:choose>
<xsl:when test="contains($next-text, $delimiter)">
<!-- recursive call -->
<xsl:call-template name="token-before-last">
<xsl:with-param name="text" select="$next-text"/>
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="substring-before($text, $delimiter)"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
Example of call:
<xsl:template match="tag">
<result>
<xsl:call-template name="token-before-last">
<xsl:with-param name="text" select="."/>
</xsl:call-template>
</result>
</xsl:template>
Demo: http://xsltransform.net/94AbWAB
If your processor supports the EXSLT str:tokenize() extension function, you can do simply:
<xsl:template match="tag">
<result>
<xsl:value-of select="str:tokenize(., '/')[last() -1]"/>
</result>
</xsl:template>
