How are methods with arguments invoked?

Question

I am trying to call a method with arguments, but it doesn't work. I have this method:

 public class AllMethods
    {
       //method change state and status of entity objetivovisitacao for "Propagado"
        public static void changeStatus(Guid objetivoId, IOrganizationService service, int state)
        {
            SetStateRequest setStateRequest = new SetStateRequest
            {
                EntityMoniker = new EntityReference("statuscode", objetivoId),
                State = new OptionSetValue(0),
                Status = new OptionSetValue(911950001),
            };
            service.Execute(setStateRequest);
        }

    }

And I need to call that method, so I tried doing it this way:

  AllMethods.changeStatus();

But it's wrong. Can someone explain this so that I can better understand what I'm missing here?

`AllMethods.changeStatus(yourGuid, yourService, yourState);` — Fabio, Aug 09 '16 at 10:54
@Claudia...read this...https://msdn.microsoft.com/en-us/library/0f66670z.aspx — dinotom, Aug 09 '16 at 10:56
as per your code it give you compile time error, you have to pass parameter value. — Sandip - Frontend Developer, Aug 09 '16 at 10:57
"But it's wrong"? What does this mean? Exceptions? Unexpected results? — MakePeaceGreatAgain, Aug 09 '16 at 10:59
Due to the number of edits it is quite unclear what you *actual* code looks like. Is it `AllMethods.changeStatus();` or `AllMethods.changeStatus(Guid objetivoId, IOrganizationService service, int state)`? Of course both are whrong. — MakePeaceGreatAgain, Aug 09 '16 at 11:03

Fabio · Accepted Answer · 2016-08-09T11:03:48.020

First create variables for the parameters of the method. Then pass them in the same order as they was declared in the method.

Guid yourObjetivoId = new Guid();
IOrganizationService yourService = New YourImplementationOfOrganizationService();
int yourState = 3;

AllMethods.changeStatus(yourObjetivoId, yourService, yourState);

From MSDN: Methods (C# Programming Guide)

The method definition specifies the names and types of any parameters that are required.
When calling code calls the method, it provides concrete values called arguments for each parameter.
The arguments must be compatible with the parameter type but the argument name (if any) used in the calling code does not have to be the same as the parameter named defined in the method

score 1 · Answer 2 · answered Aug 09 '16 at 10:57

1

No need to state the types of the parameters when passing them through. You should call it like this:

AllMethods.changeStatus(objetivoId, service, state);

answered Aug 09 '16 at 10:57

MichaelThePotato

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score 0 · Answer 3 · answered Aug 09 '16 at 10:57

0

you need to pass the parameters, see documentation: Pass parameters c#

in your case

AllMethods.changeStatus(objetivoId, service, state);

answered Aug 09 '16 at 10:57

TiGreX

1,602
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score 0 · Answer 4 · answered Aug 09 '16 at 10:59

If you declare a method like you did:

public static void changeStatus(Guid objetivoId, IOrganizationService service, int state)

you declare parameters in the parentheses. The compiler expects the necessary input when you try to call it. So you need the fitting parameters for the call of this method. It is like a key to a lock.

Guid objetivoId = // your value
IOrganizationService service = // your value
int state = // your value

then you call it like this:

AllMethods.changeStatus(objetivoId, service, state);

You don't need to declare them again in the call! it has to be done beforehand

Raktim Biswas · Answer 5 · 2016-08-09T11:06:31.627

You are doing it wrong since, you are declaring the types of the parameter here:

AllMethods.changeStatus(Guid objetivoId, IOrganizationService service, int state);

for calling this method changeStatus(...), you need to pass the variable for the parameters objetivoId, service, state.

AllMethods.changeStatus(objetivoId, service, state);

See: Passing of Parameters in C#

MSDN:

In C#, arguments can be passed to parameters either by value or by reference.

How are methods with arguments invoked?

5 Answers5