It can be done using code like the following.
function getParameterByName(name, url) {
if (!url) url = window.location.href;
name = name.replace(/[\[\]]/g, "\\$&");
var regex = new RegExp("[?&]" + name + "(=([^&#]*)|&|#|$)"),
results = regex.exec(url);
if (!results) return null;
if (!results[2]) return '';
return decodeURIComponent(results[2].replace(/\+/g, " "));
}
var googleFontUrl = 'https://fonts.googleapis.com/css?family=Droid+Serif:400,700,700i|Merriweather:300,400,700,900i|Open+Sans+Condensed:300,300i,700';
var fontFamilies = getParameterByName('family', googleFontUrl).split('|');
var fontArr = [];
fontFamilies.forEach(function(item) {
fontArr.push(item.split(':')[0]);
});
alert(fontArr.join(', '));
JSFiddle: https://jsfiddle.net/5qvpg606/
Explanation:
First, retrieve value of the family parameter from the URL using the getParameterByName function. In this example, the value of the family parameter is "Droid Serif:400,700,700i|Merriweather:300,400,700,900i|Open Sans Condensed:300,300i,700"
Then split the value into an array to get the font families. We use JS String .split() method with "|" as the separator. Now items in the array are: "Droid Serif:400,700,700i", "Merriweather:300,400,700,900i", and "Open+Sans Condensed:300".
Loop through the array, split each item (string) using ":" as the separator, get the first part (which contains family name) and push it to fontArr, so you'll get an array that contains "Droid Serif", "Merriweather", and "Open Sans Condensed".
To see the result, simply join the array: fontArr.join(', ')