multiple if and elseif statements in PHP

Question

in this case i have 69 category item and i wanted to store each of the item by the category. so, my "IF and ELSEIF" statements will looks like this

    if ($category == 1){
       echo "1";
    } 
    elseif ($category == 2){
       echo "2";
    }
    elseif ($category == 3){
       echo "3";
    }
    elseif ($category == 4){
       echo "4";
    }

if i am keep with these way, this will takes lots of time. So is there any simple way to do this? Thank you

then i have to write until 69 case? its still the same right? @Sirko — Muhammad Febrik, Aug 18 '16 at 07:12
What's the logic happening within the if/else if statements? Is it something that a database would be better suited for? — jedifans, Aug 18 '16 at 07:13
`echo category;` What are you really doing in the statements? You should add relevant code. — HiDeoo, Aug 18 '16 at 07:13
Well, what exactly is the pattern? Given what you show, the most straight-forward implementation is `echo category`. But I'll assume your *actual* use case is a bit more complex than that, no? — deceze, Aug 18 '16 at 08:04

Vinod VT · Accepted Answer · 2016-08-18T07:19:26.210

1

Try for loop,

for($i=1;$i<70;$i++){
   if($category == $i){
      echo $i;
      break;
   } 
}

edited Aug 18 '16 at 07:19

answered Aug 18 '16 at 07:13

Vinod VT

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I think this is still wrong. It will end up in many if statements – aldrin27 Aug 18 '16 at 07:15
Can be replaced by `echo $category` to do the same thing. Possibly `if ($category >= 1 && $category < 70) echo $category;`. – deceze Aug 18 '16 at 08:05

score 1 · Answer 2 · edited Aug 18 '16 at 07:49

1

use below way

$cat_arr = $result_arr_cat; // $result_arr_cat is result of category as associative
$arr_output = array('1'=>'1\'s output','2'=>'','3'=>''); // and so on
if(in_array($category,$cat_arr)){
 echo $category; // or keep the output in array of specific key echo $arr_output[$category];
}

Or even more simple

$arr_output = array(1=>'1\'s output', 2=>'', 3=>''); // and so on
if(array_key_exists($category, $arr_output)){
     echo $arr_output[$category];
}

edited Aug 18 '16 at 07:49

Rafal Kozlowski

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answered Aug 18 '16 at 07:17

AmmyTech

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You are defining `$arr_output` variable, but you are not using it – Rafal Kozlowski Aug 18 '16 at 07:18
yhea i had added comment //or keep the output in array of specific key – AmmyTech Aug 18 '16 at 07:19

score 0 · Answer 3 · answered Aug 18 '16 at 07:26

0

Short solution using in_array and range functions:

if (in_array($category, range(1, 69))) {
    echo $category;
}

answered Aug 18 '16 at 07:26

RomanPerekhrest

88,541
4
65
105

score 0 · Answer 4 · edited May 23 '17 at 10:28

0

If you're just converting an integer to the equivalent string, use typecasting.

For example: echo (string)$category;

For more info, reference this answer: ToString() equivalent in PHP

edited May 23 '17 at 10:28

Community

1
1

answered Aug 18 '16 at 07:59

Jim Bergman

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multiple if and elseif statements in PHP

4 Answers4