How does an int variable change after being declared in a result of a statement as a double?

Question

Let us say you have 2 declared variables, each being an integer.

result = variable1 / variable2;

result is a double.

What would be the values of each of the variables after the previous statement executes? Let's say variable1 is 10 and variable2 is 6

Try it and show us what you get and what you expect. – M.Hassan Sep 08 '16 at 18:49 — M.Hassan, Sep 08 '16 at 18:49

score 1 · Answer 1 · answered Sep 08 '16 at 18:48

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You would get the result 10 / 6 = 1 (integer division). Then that result would be converted to a double and assigned to result. The variables would remain what they are, of course.

answered Sep 08 '16 at 18:48

Rudy Velthuis

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I see, it makes sense to me now. Thank you sir. – mpedzi03 Sep 08 '16 at 18:51

Sourav Ghosh · Answer 2 · 2016-09-08T18:56:25.730

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Nothing changes about variable1 and variable2. They remain ints and hold their values.

Also, because both the operands of the divison are ints, the integer division will take place.

The result of the integer division is (implicitly) converted to a double and stored into result.

edited Sep 08 '16 at 18:56

answered Sep 08 '16 at 18:49

Sourav Ghosh

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Thank you this is what I thought initially I just wanted to be sure. – mpedzi03 Sep 08 '16 at 18:51

score 0 · Answer 3 · answered Sep 08 '16 at 18:49

0

variable1 will continue to be 10, and variable2 will continue to be 6. The only expressions that change variables are assignment and compound-assignment expressions (=, +=, etc., and as a special shorthand ++ for += 1 and -- for -= 1).

answered Sep 08 '16 at 18:49

Kerrek SB

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I see. I am reading into the assignments now. Thanks! – mpedzi03 Sep 08 '16 at 18:52

How does an int variable change after being declared in a result of a statement as a double?

3 Answers3