How to use regular express parse file directory hierarchy?

Question

Suppose the file path is "a/b/c/d/e", how can I get a array of 'a', 'b', 'c', 'd', 'e'?
I have consider with this: (?:(.+)/)*?(.+)
but it get empty string,it is really unexpected.

You can use `[^/]+` – Wiktor Stribiżew Sep 28 '16 at 16:11 — Wiktor Stribiżew, Sep 28 '16 at 16:11

Mustofa Rizwan · Accepted Answer · 2016-09-28T16:38:50.317

0

You can try with this one:

/([^\/]+)/g

Tested here:

Regex101

edited Sep 28 '16 at 16:38

answered Sep 28 '16 at 16:13

Mustofa Rizwan

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only get 'a' with `new Regex("([^\\/])*[\\/]*");` in c# – LoranceChen Sep 28 '16 at 16:25
could you please try now ? – Mustofa Rizwan Sep 28 '16 at 16:31
so sad it also return 'a' – LoranceChen Sep 28 '16 at 16:37
Are you sure about that ? https://regex101.com/r/yK7Igv/1 – Mustofa Rizwan Sep 28 '16 at 16:39
I'm not use `/g` in c#, I add it with `Matches` method( before is `Match` method), it works now! thanks – LoranceChen Sep 28 '16 at 16:46
Could have helped earliar, had you tagged c# – Mustofa Rizwan Sep 28 '16 at 16:47

How to use regular express parse file directory hierarchy?

1 Answers1