Simple basic relative path on file_get_content() function

Question

I'm trying to output my screen.css file contents with in <style> tag.

I thought this was the easy part, but relative path not working?

See my code...

<?php printf('<style type="text/css">%s</style>', file_get_contents('css/screen.css?v='.rand()) ); ?>

So in theory, this code is in my index.php, the relative path should find the css folder local to my php file? But I get this error...

Warning: file_get_contents(./css/screen.css?v=1836240868): failed to open stream: No such file or directory in index.php on line 18
');

See my folder my structure below...

If anyone can give me some advice or help on this that would be great.

Of course the version was causing it causing it to break, thanks @JessieJackson — joshmoto, Sep 29 '16 at 12:43
Possible duplicate of [PHP - Failed to open stream : No such file or directory](http://stackoverflow.com/questions/36577020/php-failed-to-open-stream-no-such-file-or-directory) — Vic Seedoubleyew, Oct 01 '16 at 12:24

score 0 · Answer 1 · answered Sep 07 '19 at 13:35

0

Php code



define("BASE_URI", "http://example.com/");

Html code


    <link href="<?php echo BASE_URI;?>/folder/style.css" rel="stylesheet" />

answered Sep 07 '19 at 13:35

dılo sürücü

1 Answers1