How to check given character lies between A to Z in Swift 3.0?

Question

My problem is unary operator is not in Swift 3.0 Below is my snippet.

func  checkCharacter(x: Character)  {
   if x >= "a" || x <="z"{
   }
}

How to check that given character lies between a to z in swift 3.0

score 5 · Accepted Answer · answered Oct 04 '16 at 12:16

5

Try like this.

func checkCharacter(x: Character) {

    if x >= "a" && x <= "z" {
        print("Inside character range")
    }
    else {
        print("Not inside character range")
    }
}

checkCharacter(x: "c")

answered Oct 04 '16 at 12:16

Nirav D

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I think the problem is with your `||`/ `or` operator it should be and instead of or. – Nirav D Oct 04 '16 at 12:25
>= operator in not allowed in swift3.0 – akshay Oct 04 '16 at 13:37
try to execute your code in Xcode 8. You will get error regarding unary operator. – akshay Oct 04 '16 at 13:41
yup its working but intially I got error.Now I have replaced && operator with || and its working fine. – akshay Oct 04 '16 at 13:50
@akshay You are doing wrong if you want the perfect result then it must be && not ||. – Nirav D Oct 04 '16 at 15:48

score 3 · Answer 2 · edited May 23 '17 at 11:54

I would strongly recommend using a regex like this

    let testStr = "a"
    let matches = self.matchesForRegexInText(regex: "^[a-zA-Z]+$", text: testStr)

    if matches.count > 0 {
        //string contains only a-z or A-Z
    }

func matchesForRegexInText(regex: String, text: String) -> [String] {

    do {
        let regex = try NSRegularExpression(pattern: regex, options: [])
        let nsString = text as NSString
        let results = regex.matches(in: text,
                                            options: [], range: NSMakeRange(0, nsString.length))
        return results.map { nsString.substring(with: $0.range)}
    } catch let error as NSError {
        print("invalid regex: \(error.localizedDescription)")
        return []
    }
}

edit: I stole the code without mentioning it: Swift extract regex matches

if I dont wan't to use regex .Is there any other solution to solve my problem. — akshay, Oct 04 '16 at 13:40

How to check given character lies between A to Z in Swift 3.0?

2 Answers2