What is the type definition of a variable x in this code?
typedef int *f(int);
f *x;
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ufo
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3Is it for a computer science classe assignment? – Diti Oct 05 '16 at 09:30
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@Diti , No, it isn't. – ufo Oct 05 '16 at 09:31
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f is an alias for a function type that takes int as an argument and returns an int*.
As such it isn't particularly useful.
(If you wanted f to be a pointer to a function that takes an int and returns an int, you'd have to write typedef int (*f)(int);)
Bathsheba
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Style nit-pick: the OP's style is actually quite useful for people who prefer a consistent style when they work with any kind of pointers. If you use the typedef from the OP, you can declare a function pointer variable as `f* ptr;`. Rather than hiding the pointer behind typedef as in your case, and ending up with the more mysterious declaration `f ptr;`. – Lundin Oct 05 '16 at 09:51
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typedef int* f(int);
type f is function with int parameters and returning pointer to int.
You cannot define a function using a typedef for a function type. please see the stack overflow answer.
