Basic Java String args error

Question

So I'm working on a very basic java assignment, and I believe I understand how the (String [] args) part of the main works. Basically my understanding is that the command line arguments are put into the array of strings called args. However my code won't produce the results I expect. It seems to work fine with no arguments but when I put in either of the other options I'm always greeted with my usage error.

class TicTacToe
{
  public char[][] gameboard = {  {' ', ' ', ' '},
              {' ', ' ', ' '},
              {' ', ' ', ' '}  };

  public static void main(String [] args)  {
    char play1, play2; 

    if(args.length == 0)  {
      play1 = 'h';
      play2 = 'h';
    }else if(args.length == 1 && args[0] == "-c")  {
      play1 = 'c';
      play2 = 'c';
    }else if(args.length == 2 && args[1] == "1")  {
      play1 = 'c';
      play2 = 'h';
    }else if(args.length == 2 && args[1] == "2")  {
      play1 = 'h';
      play2 = 'c';
    }else{
      System.out.println("Usage: java TicTacToe [-c [1|2]]");
      return;
    }
  }
}

The args may include any variable when you call to the main method from outside of the program. The code you have wrote is running the main method without any parameter that is why the args always empty. — Rotem, Oct 11 '16 at 16:17

Giancarlo Ventura · Answer 1 · 2016-10-11T16:24:16.597

0

You are comparing strings with '=='

You should compare strings with .equals()

edited Oct 11 '16 at 16:24

answered Oct 11 '16 at 16:15

Giancarlo Ventura

849
1
10
27

It was the .equals! I just started with java and I keep mixing it up with my c++ syntax. Thank you very much. – Sam Wilton Oct 11 '16 at 16:20
Maybe you can mark it as the answer. I dont understand the downvote :/ – Giancarlo Ventura Oct 11 '16 at 16:23
@SamWilton java (and C++) have the same C syntax. – Shark Oct 11 '16 at 16:43

Basic Java String args error

1 Answers1