How to get value of a given key if found in an array?

Question

I'm trying to get the value of a given key if found using the array_key_exists function.

$var = 35;

if(array_key_exists($var, $_SESSION['cart_items']))
{
    //give the value of found key
}
else
{
    $_SESSION['cart_items'][$var] = $anothervar;
}

For now, I only have this:

Array
(
    [35] => 3
    [41] => 6
)

So what I wanted to get is the value 3. Is there a simple way to do this?

score 1 · Answer 1 · answered Oct 13 '16 at 02:14

You can use the variable itself in the array declaration. Just put it between the [] brackets. Such as below. If you echo $the_value after that statement it should be 3.

if(array_key_exists($var, $_SESSION['cart_items'])) {
    $the_value = $_SESSION['cart_items'][$var];
}
else {
    $_SESSION['cart_items'][$var] = $anothervar;
}

score 1 · Accepted Answer · answered Oct 13 '16 at 02:15

1

Don't quite understand, but I assume your $_SESSION['cart_items'] is:

Array
(
    [35] => 3
    [41] => 6
)

Then, to get value 3, all you need is:

$_SESSION['cart_items'][$var]

answered Oct 13 '16 at 02:15

exiang

559
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14

How to get value of a given key if found in an array?

2 Answers2