Finding all the files of a certain extension in a project's source folder

Question

Hello I am trying to retrieve the names of all the files of the type .mp3 from a source folder(below)

Below is the code I am using to differentiate the file type and add to the list. However I do not know which parameter I should enter into the directory it should be music folder however I do not know how to represent this.

    File dir = new File("");
    String[] files = dir.list(new FilenameFilter() {
        public boolean accept(File dir, String name) {
            return name.toLowerCase().endsWith(".mp3");
        };
    });
    for(int a = 0; a < files.length; a++)
    {
        musicList.add(files[a]);
    }

Go into your workspace, and get the path to the music folder (right click it), and then in your code do this: File dir = new File("/path/to/music/folder"); — Brunaldo, Oct 14 '16 at 10:44
@Adam Ren which type of application you are using, i means Spring, Servlet or Simple java Application — Jay Prakash, Oct 14 '16 at 10:47

score 2 · Accepted Answer · 2020-10-06T21:25:07.680

2

Try this.

List<String> result = Files.find(Paths.get("music"), 100,
    (p, a) -> p.toString().toLowerCase().endsWith(".mp3"))
    .map(path -> path.toString())
    .collect(Collectors.toList());

edited Oct 06 '20 at 21:25

answered Oct 14 '16 at 10:53

Submitted edit for your post basically should be `.\\music` in `Paths.get();` – Politic Revolutionnaire Oct 14 '16 at 11:07

score 0 · Answer 2 · edited May 23 '17 at 12:16

0

if you are using Servlet :

ServletActionContext.getServletContext().getRealPath("music");

if using Spring :

ClassLoader classLoader = getClass().getClassLoader();
File file = new File(classLoader.getResource("music").getFile());
System.out.println(file.getAbsolutePath());

For javafx see this:

How to target a file (a path to it) in Java/JavaFX

edited May 23 '17 at 12:16

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answered Oct 14 '16 at 10:49

Jay Prakash

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Finding all the files of a certain extension in a project's source folder

2 Answers2