Ok it's not exactly clear what's going wrong because you haven't sent us precisely what you are doing, but here is my guess. If your circle.py file is as follows
import fig
class Circle(Fig):
    def __init__(self, radius):
        self.name= "Circle"
        self.data= ["Radius: ", radius]
This will break because python doesn't know where to find Fig. If instead you write 
import fig
class Circle(fig.Fig):
    def __init__(self, radius):
        self.name= "Circle"
        self.data= ["Radius: ", radius]
or 
from fig import Fig
class Circle(Fig):
    def __init__(self, radius):
        self.name= "Circle"
        self.data= ["Radius: ", radius]
Everything should work fine. This is because you either have to tell python the namespace through which it can access the class (my first solution) or explicitly import the class (my second solution). The same logic applies if you want to use PI:
import fig
class Circle(fig.Fig):
    def __init__(self, radius):
        self.name= "Circle"
        self.data= ["Radius: ", radius]
        #use PI from fig.py by informing python of namespace
        self.circumference = 2.*fig.PI*radius 
or
from fig import Fig, PI
class Circle(fig):
    def __init__(self, radius):
        self.name= "Circle"
        self.data= ["Radius: ", radius]
        #PI is now explicitly imported so don't need namespace
        self.circumference = 2.*PI*radius