Conditional tag with DateInterval

Question

how to use conditional tags using DateInterval with hour for scale in PHP

for example i will add text "active" if at 21:00 until 23:00

<?php 
  $Hr = date('H:i'); 
  if($hr == 21:00 - 23:00) { 
    echo "active"; 
  }
  else { 
    echo "not active"; 
  }

where is your code ?? Edit your question by adding your code also. — Pranav MS, Nov 11 '16 at 07:04
Read this question and answers: http://stackoverflow.com/questions/676824/how-to-calculate-the-difference-between-two-dates-using-php — Ilker Mutlu, Nov 11 '16 at 07:08

score 0 · Answer 1 · answered Nov 11 '16 at 07:22

0

$Hr = date('H:i'); 

  if(strtotime($hr)>strtotime(21:00) && strtotime($hr)<strtotime(23:00) ){
    echo "active";
  }else{
     echo "not active"; 
  }

Please try this this may work.

answered Nov 11 '16 at 07:22

Pranav MS

2,235
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23
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excelent... bit mistake on my files and successful by adding 'in ('21: 00') thanks – awnew Nov 11 '16 at 07:30

Dave · Accepted Answer · 2016-11-11T07:48:10.910

0

Try this, use DateTime to compare time.

$time1 = new DateTime('21:00');
$time2 = new DateTime('23:00');
$interval = $time1->diff($time2);
//echo $interval;
$diff =  $interval->format('%H').":".$interval->format('%I');
$Hr = date('H:i'); 
echo $diff." == ".$Hr."\n";

if($hr == $diff) { 
    echo "active"; 
}
else { 
   echo "not active"; 
}

DEMO

edited Nov 11 '16 at 07:48

answered Nov 11 '16 at 07:38

Dave

3,073
7
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Conditional tag with DateInterval

2 Answers2