How to terminate an single gulp.watch change event listener while keeping the gulp script running

Question

How to terminate an gulp.watch change event listener without terminating the rest of the gulp script?

Not an very elegant test case:

function paths() {
    var paths = JSON.parse(fs.readFileSync('../../z/paths.json'))
    gulp.watch(paths.scriptsFiles, ['test'])

    return paths
}
gulp.task('test', () =>
    gulp.src(paths().scriptsFiles)
        .pipe(...)
        .pipe(...)
)

Which leads to this error:

MaxListenersExceededWarning: Possible EventEmitter memory leak detected. 11 change listeners added. Use emitter.setMaxListeners() to increase limit

can you show what you tried? – randominstanceOfLivingThing Nov 15 '16 at 22:49 — randominstanceOfLivingThing, Nov 15 '16 at 22:49
http://stackoverflow.com/a/26176922/7045253 might helps. – KarateJB Nov 16 '16 at 01:29 — KarateJB, Nov 16 '16 at 01:29

score 0 · Accepted Answer · answered Nov 16 '16 at 10:36

0

I stumbled upon chokidar which says to be the underlying package in gulp. It is also very well documented with code examples.

answered Nov 16 '16 at 10:36

Bram z

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How to terminate an single gulp.watch change event listener while keeping the gulp script running

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