addressing an array with a "string integer" as a key PHP

Asked Nov 17 '16 at 15:42

Active Nov 17 '16 at 15:42

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I've used the json_decode function to convert the given json into an object, I can then address each of these by using something like $givenobject->name or $givenobject->productdetails->name. the problem is, instead of using a simple index for a key, the table I am trying to decode from has used an integer for the key that's being treated as a string. I cant do $givenobject->productdetails->"1"->name since that would just throw an error.

Heres an example of the given json:

{
  "id":"1",
  "info":{
    "1":{
      "name":"Example",
      "description":"Example description"
    }
  }
}

How would I extract the "name" variable from this table without having to go:

$tabledata->info->1->name

asked Nov 17 '16 at 15:42

Toaster

1

Decode it as an array -> see second parameter in `json_decode()` – nospor Nov 17 '16 at 15:44
is this fragment shown above actual and there's no other nested structures with key `name`? – RomanPerekhrest Nov 17 '16 at 15:47
1

But to answer the object question: `echo $givenobject->info->{1}->name;` Or `{'1'}` will work as well. – AbraCadaver Nov 17 '16 at 15:48
$array = json_decode($json, true); $name = $array['info'][1]['name']; echo $name; – James Nov 17 '16 at 16:44

addressing an array with a "string integer" as a key PHP

0 Answers0