Expression implicitly coerced from 'String?' to Any

Question

I have some error like this "Expression implicitly coerced from String? to Any" this is my code :

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
    // Override point for customization after application launch.

    FIRApp.configure()
    FIRAuth.auth()?.signIn(withEmail: "myemail@gmail.com", password: "mypassword", completion: { (user, error) in
        if (error != nil) {
            print(user?.email)
        }else {
            print(error?.localizedDescription)
        }
    })

    return true
}

Error in this line

print(user?.email)

And

print(error?.localizedDescription)

Please help me

You can do `user?.email as Any` to explicitly state that you want it to convert to `Any` — onmyway133, Oct 20 '20 at 12:02

score 51 · Answer 1 · answered Nov 19 '16 at 09:54

51

The print function requires a set of Any parameters. String is a Any. In this case Xcode is telling you that it implicitly coerced the optional string into an Any object (by transforming the String value in Optional(value)).

To avoid this warning, you can simply use a default value or unwrap the String?

print(user?.email ?? "User instance is nil")
print(user!.email)

answered Nov 19 '16 at 09:54

Luca D'Alberti

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1

What will happen is user is nil on the second line? – probrandono Nov 21 '16 at 06:53
2

The app will crash, of course. But after my explanation about Optional I think it was implicit – Luca D'Alberti Nov 21 '16 at 06:55
6

what a monkey job to write every time ?? "" atleast or getting ur app crash becaus of prints. why cant it just print nil where it became nil and thats it? – Zaporozhchenko Oleksandr Dec 19 '18 at 11:07
1

@ZaporozhchenkoAleksandr I totally agree with you, but my answer scope is to explain why the error happens and how to get rid of it. The best way to do it, you find it. – Luca D'Alberti Dec 20 '18 at 10:14
1

@LucaD'Alberti yes, sure. thats was just complaints about native api ;) thx for what you've done – Zaporozhchenko Oleksandr Dec 20 '18 at 10:49
@LucaD'Alberti (Caveat: I'm new to Swift.) Isn't it also true that `Optional` is an `Any`? If so, why does it complain when we pass it an `Any` in the form of an `Optional`? – Cai Apr 12 '20 at 17:57
One more option for this issue is explicitly cast to Any. `user?.email as Any`. – Ryan Jul 13 '20 at 22:41

Expression implicitly coerced from 'String?' to Any

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