Remove an item in list and get a new list?

Question

I saw there are several topics on removing items from a list, including using remove(), pop(), and del. But none of these is what I am looking for, since I want to get a new list when the items are removed. For example, I want to do this:

a = [1, 2, 3, 4, 5, 6]
<fill in >       # This step somehow removes the third item and get a new list b and let
b = [1, 2, 4, 5, 6]

How can I do this?

@barakmanos i believe it returns element and not new `list` object as OP want it. — vishes_shell, Nov 21 '16 at 10:05
@khelwood OP wants to create new list without the 3rd item, not without the int `3` — Chris_Rands, Nov 21 '16 at 10:07
@vishes_shell: It rturns `[1,2,4,5,6]`, which is exactly what OP wants (you can precede it with `b = ` if you want to store it somewhere). — barak manos, Nov 21 '16 at 10:18

score 38 · Accepted Answer · edited May 23 '18 at 23:47

38

If you want to have a new list without the third element then:

b = a[:2] + a[3:]

If you want a list without value '3':

b = [n for n in a if n != 3]

edited May 23 '18 at 23:47

Peter Mortensen

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answered Nov 21 '16 at 10:09

Yevhen Kuzmovych

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`b = a[:2] + a[3:]` it is. Thanks @Yevhen. I thought Python has something built-in function to do this, well, maybe not. But this is an excellent solution! – user3768495 Nov 21 '16 at 20:39

Remove an item in list and get a new list?

1 Answers1

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