Why is function not printing anything to console when called?

Question

When I call the vote()function, the compiler doesn't print an output. Why isn't the function printing anything to the console when I call it?

Here is my code:

def vote(vote_one, vote_two, vote_three):
    if (vote_one == vote_two):
        return True
    elif (vote_one == vote_three):
        return True
    elif (vote_two == vote_three):
        return True
    else:
        return False

vote(1, 2, 1)

Is the indentation really that way? If it is your function has no body — Sami Kuhmonen, Nov 24 '16 at 04:08
Looks good except the indentation is bad, what error msg you get ? — Skycc, Nov 24 '16 at 04:09
I forgot to indent it. That wasn't intentional. Thanks for the edit. — Darien Springer, Nov 24 '16 at 04:09
What gives that error message? The program works but it has no output. Python doesn't give an error in that case — Sami Kuhmonen, Nov 24 '16 at 04:11
It works fine, the second condition is true and so returns true — Tim, Nov 24 '16 at 04:13
You can simplify it to `return vote_one == vote_two or vote_one == vote_three or vote_two == vote_three` — Barmar, Nov 24 '16 at 04:17

Eric Frechette · Accepted Answer · 2016-11-24T04:53:20.557

3

It's because you aren't actually outputting anything. When you call vote(), a result is returned (True or False), but you aren't actually using the result. You could do

result = vote(1, 2, 1)
print(result)

or

print(vote(1, 2, 1))

edited Nov 24 '16 at 04:53

answered Nov 24 '16 at 04:16

Eric Frechette

138
2
8

Why is function not printing anything to console when called?

1 Answers1