scanf and the char variable don't get a long

Question

#include <stdio.h>
#include <conio.h>

void main(){
int turn,i=1,num;
char answer;

for(i>0;i++;){
printf("Please enter a number in the range 1-5:");
scanf("%d",&num);

if (num == 1){
    printf("Disconnecting\n");
    continue;
}

else if(num == 2){
continue;
}

else if(num == 3){
    printf("Are you sure you would like to finish your order??? \nplease enter one char:");
    scanf("%c", &answer);
        if(answer == 'y'){
            printf("Canceled");
            break;
        }

        else{
            continue;
    }
}

else if(num == 4){
turn=i-1;
printf("your position in queue is:%d\n",turn);
continue;
}

else if(num == 5){
break;
}

else {
    printf("Wrong input\n");
    continue;
}

}
getch();
}

I'm using c language for this, if You look at the

else if(num == 3)

it should function in a way that when I enter the letter y,Y it will say canceled and end the program and if not it will just reset the loop. now when I use the number 3 and give the variable c the letter 'y' it just says nothing and acts like I gave it the command "continue" + pressed the number 3 again although all I have done is press y or Y and enter. everything else is good. I would be glad if anyone can tell me how to fix that.

You do realize that after entering "3" and hitting `Enter`, and `%d` processes the input "3", the very next character that `%c` will process will be the newline character, generated by the `Enter` key, right? — Sam Varshavchik, Nov 28 '16 at 03:38

Michael Dautermann · Answer 1 · 2016-11-28T04:09:53.197

0

The getch found at the bottom of your main is being used to get order numbers.

Try putting a "getch" in right before you are looking for your y character.

That is to say, something like:

else if(num == 3){
    printf("Are you sure you would like to finish your order??? \nplease enter one char:");
    getch();
    scanf("%c", &answer);
    if((answer == 'y') || (answer == 'Y')) {
        printf("Canceled");
        exit;
    } else {
        continue;
    }
}

edited Nov 28 '16 at 04:09

answered Nov 28 '16 at 03:40

Michael Dautermann

88,797
17
166
215

that have helped me get it right but now it doesn't mather what letter i use it will allways give me the output canceled even though it should work only with y and Y – Aviv Gold Nov 28 '16 at 04:07
now with the new adding it doesn't work ,it is like it was before the getch(); and it says the "exit" is undifined – Aviv Gold Nov 28 '16 at 04:13

score 0 · Accepted Answer · answered Nov 28 '16 at 04:08

0

for(i>0;i++;){
printf("Please enter a number in the range 1-5:");
scanf("%d",&num);getchar();
//... rest of your code
}

use getchar or getch to consume extra newline character

answered Nov 28 '16 at 04:08

Jamil Farooq

131
2
9

ty so much you just fixed my problem :) – Aviv Gold Nov 28 '16 at 11:44
thankyou in fact as I can now comment on posts – Jamil Farooq Nov 29 '16 at 06:02

scanf and the char variable don't get a long

2 Answers2