num.replace(/\B(?=(\d{2})+(?!\d))/g, ",")
The above regex is not working properly.
ex- if value= 123456789 result should be= 12,34,56,789
if value= 12345678 result should be= 1,23,45,678
if value= 123456 result should be= 1,23,456
Please suggest.
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Sibeesh Venu
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smith India
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https://regex101.com/r/hL2pF2/1 try this link. Hope you will get the answer – Karthik Sivakumar Nov 29 '16 at 11:13
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@Karthik - this is for decimal as you provide. i need only for integer. – smith India Nov 29 '16 at 11:16
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@smithIndia You can create a prototype as I mentioned in my answer. Hope that helps. – Sibeesh Venu Nov 29 '16 at 11:17
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@smith http://stackoverflow.com/questions/2254185/regular-expression-for-formatting-numbers-in-javascript check this! – Karthik Sivakumar Nov 29 '16 at 11:20
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please test for 232323, result should be 2,32,323, but this regex is showing 23,23,23 – smith India Nov 29 '16 at 11:25
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@Karthik- i don't need if number is 123123123 as 123,123,123 , my requirement is 12,31,23,123 – smith India Nov 29 '16 at 11:27
1 Answers
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You can create a extension method as follows
Number.prototype.format = function(){
return this.toString().replace(/(\d)(?=(\d{3})+(?!\d))/g, "$1,");
};
var num=123456789;
alert(num.format());
Please see the demo here, it is working fine.
Sibeesh Venu
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This regex is escaping one digit, so this is not working properly. – smith India Nov 29 '16 at 11:13
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@smithIndia No, please create the prototype function and try. It seems working fine in my end. And you can give the number itself, no need for string. For that only we have created the prototype of number. – Sibeesh Venu Nov 29 '16 at 11:15
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@smithIndia Ah, my mistake sorry, I have given the regex as parameter, now I have updated it. – Sibeesh Venu Nov 29 '16 at 11:22
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@SibeeshVenu- your regex is showing 123,456, but this is wrong, my requirement is 1,23,456 – smith India Nov 29 '16 at 11:31
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@smith India I have already left office and I may be able to help you tomorrow (Now I am using mobile). Please don't mind. Thank you. – Sibeesh Venu Nov 29 '16 at 12:49