not getting the specific result json object and how to compare the two string's

Question

i want to get only gender but it shows {"face":[{"gender": {"value": "Male"}}]} i only want gender please help me how it solve JSONArray jArray = rst.getJSONArray("face"); for (int i = 0; i < jArray.length(); i++) { String gender=jArray.getJSONObject(i).getJSONObject("attribute").getString("gender"); String jsonText; jsonText = gender; textview2.setText("GENDER" + jsonText);

Firstly Please validate json mentioned in question on this [link](http://pro.jsonlint.com).Because JSON mentioned in question is wrong check response once. — Anil Ravsaheb Ghodake, Dec 08 '16 at 11:50
Your json should be like this **{"face":[{"gender": {"value": "Male"}}]}** — Anil Ravsaheb Ghodake, Dec 08 '16 at 11:54
Check the below answer with proper json result and Let me know if any error — Anil Ravsaheb Ghodake, Dec 08 '16 at 12:08

Anil Ravsaheb Ghodake · Answer 1 · 2016-12-12T06:29:25.007

Check this code:-

Case 1:This code generate only one toast

String result = "{\"face\":[{\"gender\": {\"value\": \"Male\"}}]} ";
try {
    JSONArray objJsonArray = new JSONObject(result).getJSONArray("face");
    String gender = new JSONObject(objJsonArray.getJSONObject(0).getString("gender")).getString("value");
    Toast.makeText(this, "Gender is==>" + gender, Toast.LENGTH_SHORT).show();
} catch (JSONException e) {
    e.printStackTrace();
}

Case 2:-This code generate two toasts.

String result = "{\"face\":[{\"gender\": {\"value\": \"Male\"}},{\"gender\": {\"value\": \"Female\"}}]}";
try {
    JSONArray objJsonArray = new JSONObject(result).getJSONArray("face");
    for (int i = 0; i < objJsonArray.length(); i++) {
        String gender = new JSONObject(objJsonArray.getJSONObject(i).getString("gender")).getString("value");
        Toast.makeText(this, "Gender is==>" + gender, Toast.LENGTH_SHORT).show();
    }
} catch (JSONException e) {
    e.printStackTrace();
}

Hope it solves your problem

thanks for your solution . but your code only give's me "male" value. i want male or female from the string — farhan, Dec 09 '16 at 05:10
@farhan Its giving you the **result** as the **value of gender coming in the response**.Here I am taking your json as just example. — Anil Ravsaheb Ghodake, Dec 12 '16 at 06:14

score 0 · Answer 2 · answered Dec 07 '16 at 19:35

0

Try this on the last line:

textview2.setText("GENDER" + jsonText.value);

answered Dec 07 '16 at 19:35

JKyleK

31
6

what is 'value' here ? – farhan Dec 07 '16 at 19:39
The result that's being returned is an object. This object is a key value pair. An example of a json object is:

– JKyleK Dec 07 '16 at 19:52
It is the value of the gender field of the json object. – JKyleK Dec 07 '16 at 19:53
can you explain more with above example ? – farhan Dec 07 '16 at 20:11

score 0 · Answer 3 · answered Dec 07 '16 at 22:35

On this line you are getting the entire array:

JSONArray jArray = rst.getJSONArray("face");<br>

A JSONArray is an Array of json objects.
The json object is a name value pair.
It looks like this:

jArray[{name:”John” , gender:”male”}, 
{name:”jane” , gender:”female”}, 
{name:”Mike” , gender:”male”}]<br>

This next line loops through the array that you have. Each time pulling a different json object:

1st time through = [{name:”John” , gender:”male”}
2nd time through = {name:”jane” , gender:”female”}
3rd time through = {name:”Mike” , gender:”male”}

for (int i = 0; i < jArray.length(); i++) { String On the first look i = 0

This following line is saying: retrieve the json data where the name is gender.
This returns {gender:”male”}
“gender” being the name, “male” being the value.

gender=jArray.getJSONObject(i).getJSONObject("attribute").getString("gender").value; <br>
String jsonText; jsonText = gender; 
textview2.setText("GENDER" + jsonText);

I believe there are other more efficient ways to handle this same code, but I hope this helps none the less.

can you tell me how to compare json string .something like if gender is male it will show "yes it is male" in toast else "female ".. — farhan, Dec 08 '16 at 05:24
i have teried your concept but it shows error when i put value, but there is method called valueof().what should i write inside value of ? — farhan, Dec 08 '16 at 10:35

score 0 · Answer 4 · answered Dec 08 '16 at 11:02

0

try {
        JSONObject jsonObject = new JSONObject(string);
        JSONArray jsonArray = jsonObject.getJSONArray("face");
        for(int i=0; i<jsonArray.length(); i++){
            String gender = jsonArray.getJSONObject(i).getJSONObject("gender").getString("value");
        }

    } catch (JSONException e) {
        e.printStackTrace();
    }

if you have JsonArray length 1 then no need of for loop just replace i with 0

answered Dec 08 '16 at 11:02

Dhara Patel

359
5
19

thank you . org.json.JSONException: No value for gender – farhan Dec 08 '16 at 11:09
@farhan _string_ is only for your understanding. In actual it is a json response string – Piyush Dec 08 '16 at 11:14
{"face":[{"gender":{"value":Male"}]} in this response error look properly – Dhara Patel Dec 08 '16 at 11:14
" Male " required quotes – Dhara Patel Dec 08 '16 at 11:14
W/CursorWrapperInner: Cursor finalized without prior close() 12-08 16:42:01.417 18297-18297/myproject.demofacedetection W/System.err: org.json.JSONException: No value for gender 12-08 16:42:01.417 18297-18297/myproject.demofacedetection – farhan Dec 08 '16 at 11:14
but if this is json response then then get object why you are try to getting string – Dhara Patel Dec 08 '16 at 11:16
@Piyush can i have your e-mail id ? – farhan Dec 08 '16 at 11:17
refer this ----> http://stackoverflow.com/questions/45015/safely-turning-a-json-string-into-an-object?rq=1 – Dhara Patel Dec 08 '16 at 11:18
@DharaPatel please provide me your e-mail so that i can give you my code for just simple check as i am totally new to android . well my e-mail is mohdfarhantahir@gmail.com – farhan Dec 08 '16 at 11:21
http://www.skholingua.com/android-basic/android-app-components/resources – Dhara Patel Dec 09 '16 at 05:58

not getting the specific result json object and how to compare the two string's

4 Answers4