How to run multiple shell script which does not give prompt at the end

Question

I want to run three processes which all will stop showing that the service is started and prompt will not be given. I want to automate this procedure. I tried using "&" at the end but it pops in the terminal. I tried using "sh +x script1.sh & sh +x script2.sh" I need to stop the process by pressing ctrl+c for another script to run Please help in this

You question is exceedingly terse. You can't abort a program using Ctrl C unless it is running in the foreground. — sjsam, Dec 12 '16 at 09:20
check this [question](http://stackoverflow.com/questions/356100/how-to-wait-in-bash-for-several-subprocesses-to-finish-and-return-exit-code-0), may be can help you — Joan Esteban, Dec 12 '16 at 10:03
@sjsam: You can't do it directly, but one could set up a signal handler in the foreground process, which catches the control-c, and then send the corresponding signal to the background process. — user1934428, Dec 12 '16 at 11:09

score 0 · Accepted Answer · answered Dec 12 '16 at 10:13

You need to define a general script that launches the three processes in background and waits for the user the press Control+C. Then you add a trap to the general script to launch a shutdown hook.

I think that the solution may look as this:

#!/bin/bash

end_processes() {
  echo "Shutdown hook"
  if [ -n $PID1 ]; then
    echo "Killing PID 1 = $PID1"
    kill -9 $PID1
  fi
  if [ -n $PID2 ]; then
    echo "Killing PID 2 = $PID2" 
    kill -9 $PID2
  fi
  if [ -n $PID2 ]; then                                                                                                                                                                 
    echo "Killing PID 3 = $PID3" 
    kill -9 $PID3
  fi
}

# Main code: Add trap
trap end_processes EXIT

# Main code: Launch scripts
./script1.sh &
PID1=$!

./script2.sh &
PID2=$!

./script3.sh &
PID3=$!

# Main code: wait for user to press Control+C
while [ 1 ]; do
  sleep 1s
done

Notice that:

I have added some echo messages just to test.
Trap executes a function when EXIT is received on the script. You can change the received signal by capturing only a specific signal (i.e. SIGINT)
The trap function is now killing the processes with -9. I you wish, you can send other kill signals
The $! retrieves the PID of the most recent backgroud command.
You can modify the wait loop (the last while command) to sleep firstly for the aproximate time of the processes to finish and then to wait for a more smaller time:
```
APROX_TIME=30s
POLL_TIME=2s
sleep $APROX_TIME
while [ 1 ]; do
  sleep $POLL_TIME
done
```

@Shreyas please consider [accepting this answer](https://meta.stackexchange.com/questions/5234/how-does-accepting-an-answer-work) if it was usefull. — Cristian Ramon-Cortes, Aug 09 '17 at 08:54

How to run multiple shell script which does not give prompt at the end

1 Answers1