Python user input split() and loop

Question

I am taking user input as follows: 0,1,2,3,5 The user can write any number and separate it with a comma, the input will be x,y,z,k,c

Then I am having trouble checking if any of the number after split() is invoked is 0 or more than 30.

Code-snippet:

numbers = input(user[i]['name'] + 
", assign 10 different numbers between 1-30 (separate each with a comma ','): ")
        usrNums = numbers.split()

for number in usrNums:
    if number < 1 or number > 30: 
     #Something goes here, however, not important now.

P.s. I've read a little bit on all()

Clarification: The user inputs some numbers e.g. 0,5,2,9,7,10 the usrNums = numbers.split() split() is invoked and these are stored in usrNums, then I want to check each number in usrNums [0, 5, 2, 9, 7, 10] if any of them is "0 meaning number < 1 or > 30".

EDIT: NO THIS IS NOT A DUPLICATE, I read through, How can I read inputs as integers in Python?, and it isn't the same at all. My question is about user inputting numbers with separated commas, not one number per input.

inputs are strings. Keep that in mind ;) Use `eval(number)`in the if statement — MMF, Dec 13 '16 at 14:34
Why are you telling the user to separate their inputs with a comma, and then not splitting the input on a comma? — TigerhawkT3, Dec 13 '16 at 14:39
not really a duplicate as the question is more about test than input. — Setop, Dec 13 '16 at 14:49
try : any(map(lambda i: i==0 or i>30,numbers)) # test each numbers — Setop, Dec 13 '16 at 14:51

score 0 · Answer 1 · answered Dec 13 '16 at 14:37

0

when you use split the numbers are of type string. To compare with 1 or 30 convert these to integers

numbers  = "0,1,2,3,5"
usrNums = numbers.split(",")
#usrNums ["0","1","2","3","5"]
for number in usrNums:
    if int(number) < 1 or int(number) > 30:

answered Dec 13 '16 at 14:37

ignacio.saravia

328
1
4
15

ValueError: invalid literal for int() with base 10: '0,1,2,3,4' – John Smith Dec 13 '16 at 14:39
you fotget the split(",") comma – ignacio.saravia Dec 13 '16 at 14:43

score 0 · Answer 2 · answered Dec 13 '16 at 14:37

numbers = "1,2,3,31"
for number in numbers.split(","):
    number = eval(number) # or use int(number) or float(number) as example
    if number < 1 or number > 30:
        #do something

You forget the "," in the split function and forget to convert the string into an integer.

score 0 · Accepted Answer · answered Dec 14 '16 at 04:51

0

You can use map() method.

numberString = '1, 2, 3, 4, 5, 6, 7'
numbers = map(int, numberString.split(',')) # numbers = [1, 2, 3, 4, 5, 6, 7]
for num in numbers:
    if num < 1 or num > 30:
        # Do whatever you want here...

Hope this helps! :)

answered Dec 14 '16 at 04:51

bharadhwaj

2,059
22
35

MMF · Answer 4 · 2016-12-13T14:37:59.633

-2

The input is a string. Use eval to compare to int :

for number in usrNums:
     if eval(number) < 1 or eval(number) > 30: 
     #Something goes here, however, not important now.

You also need to indicate how to split the string : input.split(',')

edited Dec 13 '16 at 14:37

answered Dec 13 '16 at 14:35

MMF

5,750
3
16
20

TypeError: unorderable types: tuple() < int() – John Smith Dec 13 '16 at 14:37
1

`eval`? Really? – TigerhawkT3 Dec 13 '16 at 14:38
@TigerhawkT3 Thank for the feedback. Can't he use it if he is sure that the user put integers ? – MMF Dec 13 '16 at 14:38
If you're sure to get integers, why not use `int`? That's what it's for. And if they're not integers, that's even more reason not to use `eval`. – TigerhawkT3 Dec 13 '16 at 14:41
@TigerhawkT3 Ok thanks ;) Then when do you use `eval` instead of `int` ? – MMF Dec 13 '16 at 14:42

Python user input split() and loop

4 Answers4