Open Specific Folder in Android with Click

Question

I'm using the code below to open a folder created by my application but it's not working, though I got it from Trying open a specific folder in android using intent.

public void openFolder() {
    SharedPreferences sharedPreferences = PreferenceManager.getDefaultSharedPreferences(this);
    String pa = sharedPreferences.getString("path", "");
    Intent intent = new Intent(Intent.ACTION_VIEW);
    Uri uri = Uri.parse(pa);
    intent.setDataAndType(uri, "*/*");
    startActivity(Intent.createChooser(intent, "Open folder"));
}

When I am sing Action_View, it shows all possible means except FileManager and in ACTION_GET_CONTENT it took me to SAF mode like to choose storage and then specific folders.

How will it open my defined URI folder directly? Is there any other way?

refer http://stackoverflow.com/questions/17165972/android-how-to-open-a-specific-folder-via-intent-and-show-its-content-in-a-file — sasikumar, Dec 22 '16 at 05:25

score 0 · Answer 1 · answered Dec 22 '16 at 05:19

0

This should work...

SharedPreferences sharedPreferences = PreferenceManager.getDefaultSharedPreferences(this);
String file= sharedPreferences.getString("path", "");
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setDataAndType(Uri.fromFile(Environment.getExternalStorageDirectory().getPath() + file), "*/*");
startActivity(Intent.createChooser(intent, getString(R.string.open_folder)));

answered Dec 22 '16 at 05:19

Arpit Patel

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It is giving error on intent.setData as we are giving string instead of file as required. – Panache Dec 22 '16 at 05:37

Open Specific Folder in Android with Click

1 Answers1