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var myName = {
        name : 'Rakesh',
        yearOfBirth : '1981',
        calculateAge : function(){
            console.log(this);
            console.log(2016 - this.yearOfBirth);

            function innerFunction(){
                console.log("Hello World");
            }
            innerFunction();
        }

    }
Tushar
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user1613478
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  • `myName.calculateAge()` will call the `calculateAge` method and `innerFunction();` at the end of it will call `innerFunction`. – Tushar Dec 28 '16 at 11:23
  • Possible duplicate of http://stackoverflow.com/questions/7295634/javascript-nested-function – Akshay Tilekar Dec 28 '16 at 11:25

2 Answers2

0

Javascript has function scope. So, normally you can't access innerFunction() in javascript from out side.

Unless you attach that function to an object outside.

var dummy = {};

var myName = {
            name : 'Rakesh',
            yearOfBirth : '1981',
            calculateAge : function(){
                console.log(this);
                console.log(2016 - this.yearOfBirth);

                function innerFunction(){
                    console.log("Hello World");
                };

                innerFunction();

                dummy.innerFunction = innerFunction;

            }

        }

// Then you can do
myName.calculateAge(); // After you run this line, you will have dummy.innerFunction available
dummy.innerFunction();

That is a very dumb way to do it.

vothaison
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0

There are many ways to do this, one would be - 

var myName = {
  name: 'Rakesh',
  yearOfBirth: '1981',
  calculateAge: function() {
    console.log(this);
    console.log(2016 - this.yearOfBirth);
    function innerFunction() {
      console.log("Hello World");
    };
    return innerFunction;
  }
}

myName.calculateAge()();
Dhruv
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