Error using cout with pointer value

Question

I have problem in the following code:

int *ary = new int[2];
ary[0] = 1;
ary[1] = 2;

cout << &ary[0];   //no error
cout << &ary[0] + " " + &ary[1];  //error (expression must have integral or unscoped enum type  )

I cant understand why arise error using pointer value with string(integral)

What you are doing is adding unrelated pointers together, not creating strings. Perhaps you should [find a good beginners book](http://stackoverflow.com/questions/388242/the-definitive-c-book-guide-and-list) and start from the beginning? — Some programmer dude, Dec 29 '16 at 08:40

score 3 · Accepted Answer · answered Dec 29 '16 at 08:36

3

cout "streams" data into the standard output using the << operator. Not the + operator.

cout << &ary[0] << " " << &ary[1];

The way you wrote it before attempted to add 2 int* with a char[2], which aren't valid types to add with each other.

answered Dec 29 '16 at 08:36

StoryTeller - Unslander Monica

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oops I have used java for a time. lol. that is my mistake. thanks. – M.K Che Dec 29 '16 at 09:02

Error using cout with pointer value

1 Answers1