Error: java.lang.IndexOutOfBoundsException: Invalid index 2, size is 2

Question

How to remove the seperator line in footerLayout? I have a footerLayout below the listView, used to display the totalAmount as shown below. If I click the seperator line in footerLayout, my app crashed.

My MainActivity

AllAdapter obj = new AllAdapter(getApplication(), search, listview,imageView,text,button);
footerLayout = (LinearLayout) getLayoutInflater().inflate(R.layout.under_listview, null);
totalAmount = (TextView) footerLayout.findViewById(R.id.amount);

LogCat error

 java.lang.IndexOutOfBoundsException: Invalid index 2, size is 2
            at java.util.ArrayList.throwIndexOutOfBoundsException(ArrayList.java:251)
            at java.util.ArrayList.get(ArrayList.java:304)
            at com.example.tony.monthlyexpenses.adapter.AllAdapter.getItem(AllAdapter.java:61)
            at com.example.tony.monthlyexpenses.QuickExpenses$1.onItemClick(QuickExpenses.java:88)
            at android.widget.AdapterView.performItemClick(AdapterView.java:301)

The error pointed to listView onClickListener

 listview.setOnItemClickListener(new AdapterView.OnItemClickListener() {
            public void onItemClick(AdapterView<?> listView, View view, final int position, long id) {
                mClickedPosition = position;
                Expenses o = (Expenses) obj.getItem(position);
                String day = o.getDate();
            }
        });

AllAdapter

 public Expenses getItem(int position) {
        return search.get(position);
    }

The footerLayout is supposed to be displayed outside the listView, not inside. How can I get rid of this ?

I also have activity_main.xml, AllAdapter class, all_adapter.xml for ListView and also under_listview.xml for the footerLayout.

activity_main

AllAdapter

under_listview

How to move the footerLayout out from the ListView ?

I add android:footerDividersEnabled="false" now become like this

But still clickable !!!

@Swas_99 edited. I have 3 xml, one is activity_main, another is adapter, lastly is footer layout xml. Let me know which xml . — Hoo, Jan 05 '17 at 07:01
So is the issue, the footer is in the list view and the position is greater than the number of objects in obj? Maybe you should just add a check before you do getItem. — matt, Jan 05 '17 at 10:08
@Hoo Do you ave an custom litViewAdapter? If so, could you please provide your full listViewAdapter? — Malik, Jan 05 '17 at 13:04
@malik The title of the question seems to imply op is not clear about that detail. — matt, Jan 05 '17 at 14:09
Possible duplicate of [How to avoid ArrayIndexOutOfBoundsException or IndexOutOfBoundsException?](https://stackoverflow.com/questions/32568261/how-to-avoid-arrayindexoutofboundsexception-or-indexoutofboundsexception) — , Aug 28 '17 at 15:20

score 2 · Accepted Answer · answered Jan 06 '17 at 09:11

The footerLayout is supposed to be displayed outside the listView, not inside.

Actually, the footer is also part of the ListView and it adds up to the number of items the list has. Neverhteless, there are a few approaches how to ignore the click events on a footer view.

One option is instead of adding your view using:
addFooterView(footerLayout);,
use:
addFooterView(footerLayout, null, false);

The third parameter specifies whether the footer view should be selectable or not.

Another option would be to ignore the click when the position parameter is bigger than the size of your adapter dataset:

 listview.setOnItemClickListener(new AdapterView.OnItemClickListener() {
     public void onItemClick(AdapterView<?> listView, View view, final int position, long id) {
          if(position < adapter.getCount()){ 
              Expenses expenses = (Expenses) adapter.getItem(position);
              String day = expenses.getDate();
          }
     }
 });

THANKS ! `addFooterView(footerLayout, null, false);` did the tricks. — Hoo, Jan 06 '17 at 09:16

score 1 · Answer 2 · answered Jan 05 '17 at 15:19

1

Try to set the following line in your listview.

            android:footerDividersEnabled="false"

answered Jan 05 '17 at 15:19

Parin Parikh

385
1
6

add it to your ListView in xml – Jagruttam Panchal Jan 05 '17 at 15:25

score 1 · Answer 3 · answered Jan 06 '17 at 08:05

I change this code and it works fine now.

listview.setOnItemClickListener(new AdapterView.OnItemClickListener() {
            public void onItemClick(AdapterView<?> listView, View view, final int position, long id) {
                Expenses o = (Expenses) listView.getAdapter().getItem(position);
                if(o != null){
                    mClickedPosition = position;
                    //Expenses o = (Expenses) obj.getItem(position);
                    String day = o.getDate();
                }
            }
        });

score 0 · Answer 4 · answered Jan 05 '17 at 13:37

just a quick tutorial, if you are new to custom ListViewAdapters.

I would have an Object Expense like this:

class Expense {

  Date date = new Date();
  Double spendMoney = 5.0;
  Bitmap image;
  ...

  /** Continue with POJO **/
}

and an expenses_list_item.xml layout. (if you need help with that, i can add it later...)

In my MainActivity I would have an ArrayList<Expense> expensesList and
my custom ArrayListAdapter would look something like this:

class expenseListAdapter extends ArrayAdapter<Expense> {

    expenseListAdapter() {
        super(context, R.layout.expenses_list_item, expensesList);
    }

    @Override
    public View getView(int pos, View view, ViewGroup parent) {
        if (view == null) {
            view = getActivity().getLayoutInflater().inflate(R.layout.list_item_series, parent, false);
        }

        ShowListItem current = expensesList.get(pos);

        TextView expens = (TextView) view.findViewById(R.id.expenseText);
        expens.setText(current.getSpendMoney());

        ... (all other needed values of your Expense object)

        return view;
    }
}

And finally, I could just set

ArrayAdapter<Expense> adapter = new expenseListAdapter();
expenseListView.setAdapter(adapter);

That would be it. Maybe a little bit complicated on the first look, but this method is very powerfull. If you need help, don't be afraid to ask ;)

Greets Malik

Thanks, Malik,I have all these. I will update my post – Hoo Jan 05 '17 at 14:35 — Hoo, Jan 05 '17 at 14:35

Error: java.lang.IndexOutOfBoundsException: Invalid index 2, size is 2

4 Answers4