Module object not callable

Question

This is my folder structure:

script.py
api/
   __init__.py
   charts/
         __init__.py
         charts.py

In script.py, I have:

from api.charts import charts
import billboard

and the call:

charts('Alternative-Songs', '1997')

billboard.py is not in the above structure because it was installed on my system via python setup.py install, and it has the methods for charts(), like so:

billboard.ChartData(chart_name, date)

at charts.py, charts() was defined using a billboard.py method:

def charts(chart_name, date):
    chart = billboard.ChartData(chart_name, date, quantize=True)
    return chart

but when I run script.py, I get the following error:

Traceback (most recent call last):
  File "script.py", line 70, in <module>
    print (charts('Alternative-Songs', '1997'))
TypeError: 'module' object is not callable

How do I fix this?

Try putting `from charts import *` in `__init__.py` in `charts/` — juanpa.arrivillaga, Jan 08 '17 at 22:06

score 1 · Accepted Answer · answered Jan 08 '17 at 21:48

given your folder structure, charts directory contains a charts.py file.

So from api.charts import charts imports name charts as a module.

Seems that the charts module has a function called charts. You think you're calling the function but you're calling the module.

just do

print (charts.charts('Alternative-Songs', '1997'))

(that makes a lot of charts if you ask me :))

score 1 · Answer 2 · edited May 23 '17 at 11:46

1

from api.charts import charts

imports the module charts.py from the chart directory under api. (see this question for modules aliasing and importing)

Now chart is a module reference, not the method charts.

To call charts, you'll have to use

print(charts.charts('Alternative-Songs', '1997'))

(method charts inside module charts).

edited May 23 '17 at 11:46

Community

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answered Jan 08 '17 at 21:50

Uriel

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Module object not callable

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