Error zip argument #1 must support iteration

Question

When I try to execute this code

g = [1, 2, 3, 4, 5, 6]
zip(*g)

I get the following error

zip argument #1 must support iteration

I am trying to convert row into column vector

I even tried map(list, zip(*gate)) still I get the same error

Please help

The reason he wrote this is that there are other answers by knowledgeable python folks that _do_ use `zip(*g)` . E.g. here https://stackoverflow.com/a/43437266/1056563 — WestCoastProjects, Apr 20 '20 at 18:38

score 6 · Answer 1 · answered Jan 14 '17 at 13:18

With zip(*g) syntax, you are doing list unpacking. The following code:

g = [1, 2, 3, 4, 5, 6]
zip(*g)

Is equivalent to:

zip(1, 2, 3, 4, 5, 6)

Since g list contains int values (but not iterable collection) you get an error.

notice: the zip function can have a variable list of parameters.

So, to fix your problem you need to write:

zip(g)

Remember that, in Python 3, zip return a generator. To get a list you need to use the list function:

>>> list(zip([1, 2, 3, 4, 5, 6]))
[(1,), (2,), (3,), (4,), (5,), (6,)]

Thx for the answer: it's not your fault that python makes simple things unnecessarily hard / brittle. — WestCoastProjects, Apr 20 '20 at 18:38

1 Answers1