How to concatenate char with numbers via loops

Question

I have make a set of names in this form: 's1', 's2', ..., 's100'. I thought I can do that easily via looping:

for i in range(100):
    print ('s'.format(i+1))

format here does not append the numbers. I only get ss..ss without the numbers being concatenated in single quote. I know how to do this in Java but I am not that much expert in Python. Thank you

I sense an [XY Problem](http://meta.stackexchange.com/questions/66377/what-is-the-xy-problem). Why do you want to do this? — TigerhawkT3, Jan 17 '17 at 03:49
Also, couldn't you have read the documentation for the function you're trying to use? — TigerhawkT3, Jan 17 '17 at 03:53

score 3 · Accepted Answer · answered Jan 17 '17 at 03:39

3

You need to have a placeholder in the format string:

Perform a string formatting operation. The string on which this method is called can contain literal text or replacement fields delimited by braces {}. Each replacement field contains either the numeric index of a positional argument, or the name of a keyword argument.

for i in range(100):
    print ('s{0}'.format(i+1))

answered Jan 17 '17 at 03:39

alecxe

462,703
120
1,088
1,195

This works GREAT. Thank you so much – Kristofer Jan 17 '17 at 03:45

Peter Pei Guo · Answer 2 · 2017-01-17T03:45:11.500

2

If you use 3.6, then you can take advantage of the new 'Literal String Interpolation', and do the following:

for i in range(100):
    print(f's{i + 1}')

For more details on this feature, check out PEP 498 -- Literal String Interpolation

edited Jan 17 '17 at 03:45

answered Jan 17 '17 at 03:42

Peter Pei Guo

7,770
18
35
54

Unfortunately, I have to use Python 2x since my simulation supports it. Is there a workaround of that? – Kristofer Jan 17 '17 at 03:44
in that case, just do what @alecxe suggested. – Peter Pei Guo Jan 17 '17 at 03:47

How to concatenate char with numbers via loops

2 Answers2