My question is a design question. I have two custom fragments CustomFrag1 and CustomFrag2. Both these fragments have a method swapCursor. 
CustomFrag1:
public class CustomFrag1 extends Fragment {
    @Override
    public void onCreate(Bundle savedInstanceState) {
        // .... code
    }
    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container,
                             Bundle savedInstanceState) {
        // .... code
        MyAdapter mAdapter = new MyAdapter(); 
        // .... code
    }
    public static void swapCursor(final Cursor cursor, Activity ctx){
        // .... code
    }
}
CustomFrag2:
public class CustomFrag1 extends Fragment {
    @Override
    public void onCreate(Bundle savedInstanceState) {
        // .... code
    }
    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container,
                             Bundle savedInstanceState) {
        // .... code
        MyAdapter mAdapter = new MyAdapter(); 
        // .... code
    }
    public static void swapCursor(final Cursor cursor, Activity ctx){
        // .... code
    }
}
I don't want to make a seperate adapter class for each fragment. I do however, want to call swapCursor in the adapter class. If the adapter has been instantied from CustomeFrag1 I want swapCurosr to swap the cursor in CustomFrag1. If the adapter has been instantiated from CustomeFrag2 I want swapCurosr to swap the cursor in CustomFrag2.   
Is it possible to pass in an instance of the Fragment...
MyAdapter mAdapter = new MyAdapter(this);
...and somehow represent that instance with a generic variable that has swapCursor defined as a method? If not, what strategy can I use? Interfaces? Generics? Something?
edit
I tried inheriting swapCursor but that would just swap out the cursor out on the parent and not the child. 
 
     
    