while loop. random number appearing

Question

#include <iostream>

using namespace std;

int main()
{

    double number;

    while(number <= 100)
    {
        cout << number << endl;
        number++;
    }
    return 0;
}

I understand that I need to initialize the variable, but out of curiosity, why does the compiler print out this very small number at the beginning of the output?

Because it can. When undefined behavior is invoked, the compiler is allowed to print any junk, or even make a program that crashes. — Sergey Kalinichenko, Feb 03 '17 at 01:50
initialise "number" variable. local variables will not initialise to 0. If not initialised some memory will be used at run time which can have any value inside. — rajesh6115, Feb 03 '17 at 01:51
It doesn't show it [here](http://ideone.com/teWJCJ). That's undefined behavior in action. — PaulMcKenzie, Feb 03 '17 at 01:55

score 2 · Answer 1 · answered Feb 03 '17 at 01:53

2

That because you not initialize value for number ... You can check cout<< number; before loop. You can see the output..

answered Feb 03 '17 at 01:53

MAS. John

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while loop. random number appearing

1 Answers1