How do I properly use the less than and greater than sign in Python

Question

So I have the following function in my script:

def age():
    global age
    age = raw_input("Age: ")

    if age == 14:
        sleep(1)
        print ("LOL, same")
    
    elif age < 18:
        sleep(1)
        print ("This test is made for contestants older than ten")
        introduction()  
        
    elif age > 18:
        sleep(1)
        print ("Geez grandpa, you sure are old")

When I run this, it registers every age I type as above 18 like so:

Could you tell me your age?

Age: 4

Geez grandpa, you sure are old

Why does it do this?

Change `age = raw_input("Age: ")` to `age = int(raw_input("Age: "))`. The result of `raw_input` is a string, which Python 2.7 will allow you to compare with an `int` — roganjosh, Feb 05 '17 at 10:22
`raw_input()` returns a string, not an integer. You'll have to convert it first if you want to compare that with other integers. See the duplicate. — Martijn Pieters, Feb 05 '17 at 10:23
You should use Python 3; it won’t fail silently on these types of errors. — Ry-, Feb 05 '17 at 10:23

score 3 · Answer 1 · answered Feb 05 '17 at 10:22

3

As raw_input returns the user input as a string type, you should cast it into int.

Change this :

age = raw_input("Age: ")

To:

age = int(raw_input("Age: "))

answered Feb 05 '17 at 10:22

omri_saadon

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Sir, I need to talk with you, Can we chat ? – Suraj Jain Feb 05 '17 at 14:55
Yes, No problem @SurajJain – omri_saadon Feb 05 '17 at 14:57
Can you create chat ? – Suraj Jain Feb 05 '17 at 14:57

score 0 · Answer 2 · answered Feb 05 '17 at 10:23

0

your raw_input is taken as string

age = raw_input("Age: ")

so you need to convert it into a integer value if you want to compare it against numbers..

age = int(raw_input("Age: "))

answered Feb 05 '17 at 10:23

ΦXocę 웃 Пepeúpa ツ

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How do I properly use the less than and greater than sign in Python

2 Answers2