Why doesn't parameter value get replaced?

Question

I have this snippet of code

function(memo, value, key) {
    if (!!value) {
      memo.push({
        'property': 'loopbackFilter',
        'value': {
          key : {
            'like' : '%' + value + '%'
          }
        }
      });
    }
    return memo;
  }

Sublime Text says that "key" parameter is not being used, and in fact the resulting JSON object is

"where": {
  "key": { <--- key is literally "key"
    "like": "%value%" (VALUE is an actual value, so it works here)
  }
}

Why does this happen?

Christian Zosel · Accepted Answer · 2017-02-21T11:15:58.350

0

JS object literals are different than JSON objects: In JavaScript you don't need to quote the property names:

var obj = { foo: "bar" }

For computed property names use the bracket syntax:

[key] : {
  'like' : '%' + value + '%'
}

Please also note that this is an ES6 feature.

edited Feb 21 '17 at 11:15

answered Feb 21 '17 at 11:12

Christian Zosel

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Just a pointer, you currently does not enough reps to close, but when you do get them, **Please choose to close** instead of answering. – Rajesh Feb 21 '17 at 11:15
Alright, thanks for the hint! – Christian Zosel Feb 21 '17 at 11:17
Thank you for the answer, is there another way to do this? My app crashes when I try to compile it and I think it's because it's an EC6 only solution – ITKinq Feb 21 '17 at 11:39
Yes, there is! See this answer for how to do it with ES5: http://stackoverflow.com/questions/2274242/using-a-variable-for-a-key-in-a-javascript-object-literal – Christian Zosel Feb 21 '17 at 11:41
Thank you Christian! Question closed – ITKinq Feb 21 '17 at 11:42

Why doesn't parameter value get replaced?

1 Answers1